Optimal. Leaf size=94 \[ -\frac{b \text{PolyLog}\left (2,1-\frac{2}{c x+1}\right )}{2 c^2 d}+\frac{\log \left (\frac{2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{c^2 d}+\frac{a x}{c d}+\frac{b \log \left (1-c^2 x^2\right )}{2 c^2 d}+\frac{b x \tanh ^{-1}(c x)}{c d} \]
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Rubi [A] time = 0.10252, antiderivative size = 94, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {5930, 5910, 260, 5918, 2402, 2315} \[ -\frac{b \text{PolyLog}\left (2,1-\frac{2}{c x+1}\right )}{2 c^2 d}+\frac{\log \left (\frac{2}{c x+1}\right ) \left (a+b \tanh ^{-1}(c x)\right )}{c^2 d}+\frac{a x}{c d}+\frac{b \log \left (1-c^2 x^2\right )}{2 c^2 d}+\frac{b x \tanh ^{-1}(c x)}{c d} \]
Antiderivative was successfully verified.
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Rule 5930
Rule 5910
Rule 260
Rule 5918
Rule 2402
Rule 2315
Rubi steps
\begin{align*} \int \frac{x \left (a+b \tanh ^{-1}(c x)\right )}{d+c d x} \, dx &=-\frac{\int \frac{a+b \tanh ^{-1}(c x)}{d+c d x} \, dx}{c}+\frac{\int \left (a+b \tanh ^{-1}(c x)\right ) \, dx}{c d}\\ &=\frac{a x}{c d}+\frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2}{1+c x}\right )}{c^2 d}+\frac{b \int \tanh ^{-1}(c x) \, dx}{c d}-\frac{b \int \frac{\log \left (\frac{2}{1+c x}\right )}{1-c^2 x^2} \, dx}{c d}\\ &=\frac{a x}{c d}+\frac{b x \tanh ^{-1}(c x)}{c d}+\frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2}{1+c x}\right )}{c^2 d}-\frac{b \int \frac{x}{1-c^2 x^2} \, dx}{d}-\frac{b \operatorname{Subst}\left (\int \frac{\log (2 x)}{1-2 x} \, dx,x,\frac{1}{1+c x}\right )}{c^2 d}\\ &=\frac{a x}{c d}+\frac{b x \tanh ^{-1}(c x)}{c d}+\frac{\left (a+b \tanh ^{-1}(c x)\right ) \log \left (\frac{2}{1+c x}\right )}{c^2 d}+\frac{b \log \left (1-c^2 x^2\right )}{2 c^2 d}-\frac{b \text{Li}_2\left (1-\frac{2}{1+c x}\right )}{2 c^2 d}\\ \end{align*}
Mathematica [A] time = 0.154252, size = 75, normalized size = 0.8 \[ \frac{-b \text{PolyLog}\left (2,-e^{-2 \tanh ^{-1}(c x)}\right )+2 a c x-2 a \log (c x+1)+b \log \left (1-c^2 x^2\right )+2 b \tanh ^{-1}(c x) \left (c x+\log \left (e^{-2 \tanh ^{-1}(c x)}+1\right )\right )}{2 c^2 d} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.04, size = 157, normalized size = 1.7 \begin{align*}{\frac{ax}{cd}}-{\frac{a\ln \left ( cx+1 \right ) }{{c}^{2}d}}-{\frac{b{\it Artanh} \left ( cx \right ) \ln \left ( cx+1 \right ) }{{c}^{2}d}}+{\frac{bx{\it Artanh} \left ( cx \right ) }{cd}}-{\frac{b\ln \left ( cx+1 \right ) }{2\,{c}^{2}d}\ln \left ( -{\frac{cx}{2}}+{\frac{1}{2}} \right ) }+{\frac{b}{2\,{c}^{2}d}\ln \left ( -{\frac{cx}{2}}+{\frac{1}{2}} \right ) \ln \left ({\frac{1}{2}}+{\frac{cx}{2}} \right ) }+{\frac{b}{2\,{c}^{2}d}{\it dilog} \left ({\frac{1}{2}}+{\frac{cx}{2}} \right ) }+{\frac{b \left ( \ln \left ( cx+1 \right ) \right ) ^{2}}{4\,{c}^{2}d}}+{\frac{b\ln \left ( \left ( cx-1 \right ) \left ( cx+1 \right ) \right ) }{2\,{c}^{2}d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{1}{4} \,{\left (c^{2}{\left (\frac{2 \, x}{c^{3} d} - \frac{\log \left (c x + 1\right )}{c^{4} d} + \frac{\log \left (c x - 1\right )}{c^{4} d}\right )} + 2 \, c^{2} \int \frac{x^{2} \log \left (c x + 1\right )}{c^{3} d x^{2} - c d}\,{d x} - 4 \, c \int \frac{x \log \left (c x + 1\right )}{c^{3} d x^{2} - c d}\,{d x} - \frac{2 \,{\left (c x - \log \left (c x + 1\right )\right )} \log \left (-c x + 1\right )}{c^{2} d} + \frac{\log \left (c^{3} d x^{2} - c d\right )}{c^{2} d} - 2 \, \int \frac{\log \left (c x + 1\right )}{c^{3} d x^{2} - c d}\,{d x}\right )} b + a{\left (\frac{x}{c d} - \frac{\log \left (c x + 1\right )}{c^{2} d}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b x \operatorname{artanh}\left (c x\right ) + a x}{c d x + d}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{a x}{c x + 1}\, dx + \int \frac{b x \operatorname{atanh}{\left (c x \right )}}{c x + 1}\, dx}{d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b \operatorname{artanh}\left (c x\right ) + a\right )} x}{c d x + d}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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